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Chemical

Arrhenius rate constant

How a reaction rate constant changes with temperature.

Ref
CHE-05
Rev
v1
Field
Chemical
Result
k [1/s]

k rate constant, k0 pre-exponential factor (same units as k), Ea activation energy in J/mol, Ru = 8.314 J/(mol·K) and T absolute temperature in kelvin.

Reactions speed up sharply with temperature because more molecules have enough energy to react. A high activation energy makes the rate especially sensitive to temperature.

Calculator

Solve for
1/s
1/s
1,0001e12
kJ/mol
20150
K
250500
  • Exponent Ea/(RuT)20.62
  • Rate at T + 10 K ÷ rate at T1.773 ×

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Rate constant (1/s) current value 0.0111 1/s
EaActivation energyKey driver
4.1e-1610,400
k0Pre-exponential factor
1.11e-61,110
TTemperature
2.91e-65.39
  • A rough rule: the reaction rate rises by a factor of about 1.5 to 3 for each 10 K, depending on the activation energy.
  • A plot of ln k against 1/T is a straight line whose slope is −Ea/R, used to find Ea from experiments.
  • Storing energetic materials cool is effective precisely because of this exponential temperature dependence.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (1/s)Local stepChange in result
Ea Activation energy20 to 150 kJ/mol4.101e-1610,35010,350+10%−87.3 %
k0 Pre-exponential factor1,000 to 1e12 1/s1.11e-61,1101,110+10%+10 %
T Temperature250 to 500 K2.906e-65.395.39+10%+552 %

Sweep of Temperature

Temperature (K)Rate constant (1/s)
2502.906e-6
281.37.181e-5
312.59.345e-4
343.80.007627
3750.04387
406.30.1928
437.50.6857
468.82.059
5005.39

Sweep one variable

Rate constant (1/s)Hover, touch, or use the arrow keys on the chart
012345 250300350400450500 Temperature (K) now 0.0111

Variables and how each one contributes

k

Rate constant

Result · 1/s

What the equation gives you. Everything else feeds it.

k0

Pre-exponential factor

1/s · typical 1,000 to 1e12

Frequency factor. Directly proportional.

Ea

Activation energy

kJ/mol · typical 20 to 150

Energy barrier for the reaction. Strong: higher barrier lowers k exponentially.

T

Temperature

K · typical 250 to 500

Absolute temperature. Strong: k rises roughly 1.5–3× for every 10 K at typical activation energies.

Worked example with the values above

  1. Exponent: Ea/(RuT) = 60,000 / (8.314 × 350) = 20.62.
  2. e−20.62 = 1.11×10−9.
  3. k = 1×107 × 1.11×10−9 = 0.0111 s⁻¹.

Assumptions and limits

  • Single-step reaction with constant Ea.
  • Absolute temperature in kelvin.
  • Range where Arrhenius behaviour holds.

Common mistakes

  • Using °C.
  • Mixing kJ/mol with J/mol.
  • Extrapolating widely beyond measured temperatures.

Statistics and uncertainty

The exponent magnifies errors: a 10 kJ/mol error in Ea at 350 K changes k by a factor of about 31. Temperatures must be known to within a degree or so to be useful. Treat the result as an order-of-magnitude estimate unless fitted to your own data.

Where it is used

  • Ageing and shelf-life prediction of propellants and batteries.
  • Thermal runaway estimates.
  • Accelerated life testing.

Maths you need

  • Exponentials: e^(−x)
  • Absolute temperature: kelvin

Related formulas

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