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Library / Foundations: Chemistry / FCH-15

Foundations: Chemistry

Dilution

Concentration after adding solvent to a stock solution.

Ref
FCH-15
Rev
v1
Field
Foundations: Chemistry
Result
c₂ [mol/dm³]

The amount of solute stays the same, so c₁V₁ = c₂V₂. V₂ is the final volume (not the volume of water added). Both volumes must use the same unit.

Adding water does not change how much solute you have; it just spreads it through more volume.

Calculator

Solve for
mol/dm³
mol/dm³
0.00120
cm³
0.11,000
cm³
15,000
  • Dilution factor10
  • Water to add225 cm³

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Final concentration (mol/dm³) current value 0.2 mol/dm³
V₂Final volumeKey driver
0.0150
V₁Volume of stock
8e-48
c₁Initial concentration
1e-42
  • Tenfold dilution: take 25 cm³ and make up to 250 cm³.
  • Serial dilutions repeat the same factor and multiply, so three tenfold steps give a 1000-fold dilution.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (mol/dm³)Local stepChange in result
V₂ Final volume1 to 5,000 cm³0.015049.99+10%−9.09 %
V₁ Volume of stock0.1 to 1,000 cm³8e-487.999+10%+10 %
c₁ Initial concentration0.001 to 20 mol/dm³1e-422+10%+10 %

Sweep of Final volume

Final volume (cm³)Final concentration (mol/dm³)
150
2.917.24
8.4095.946
24.382.05
70.710.7071
2050.2438
594.60.08409
1,7240.029
5,0000.01

Sweep one variable

Final concentration (mol/dm³)Hover, touch, or use the arrow keys on the chart
01020304050 1101001000 Final volume (cm³), log scale now 0.2

Variables and how each one contributes

c₂

Final concentration

Result · mol/dm³

What the equation gives you. Everything else feeds it.

c₁

Initial concentration

mol/dm³ · typical 0.001 to 20

Stock concentration. Directly proportional.

V₁

Volume of stock

cm³ · typical 0.1 to 1,000

Volume of stock solution taken. Directly proportional.

V₂

Final volume

cm³ · typical 1 to 5,000

Total volume after dilution. Inversely proportional.

Worked example with the values above

  1. Moles of solute: 2 × 25 = 50 mmol (unchanged).
  2. Final volume: 250 cm³.
  3. c₂ = 50 / 250 = 0.2 mol/dm³.

Assumptions and limits

  • Solute does not react or evaporate.
  • Volumes are additive.

Common mistakes

  • Using the volume of water added for V₂.
  • Mixing cm³ and dm³ on the two sides.

Statistics and uncertainty

Pipette errors (±0.06 cm³ on 25 cm³, 0.24%) carry through each step of a serial dilution.

Where it is used

  • Preparing working solutions.
  • Calibration standards.

Maths you need

  • Concentration: mol/dm³
  • Ratios: dilution factor

Related formulas

Practise this formula