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Library / Foundations: Physics / FPH-06

Foundations: Physics

Average force from momentum change

Force needed to change momentum in a given time.

Ref
FPH-06
Rev
v1
Field
Foundations: Physics
Result
F [N]

The impulse FΔt equals the change in momentum. Use the same direction for u and v.

Changing momentum takes a force acting over time; a shorter time means a much bigger force.

Calculator

Solve for
N
kg
0.001100
m/s
020
m/s
21100
ms
0.5100
  • Impulse FΔt4.8 N·s
  • Force as multiple of weight611.8 ×

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Average force (N) current value 960 N
mMassKey driver
6600,000
ΔtContact time
489,600
vFinal velocity
6723,200
uInitial velocity
320
  • Crumple zones, airbags and padding all lengthen the stopping time to reduce the force.
  • The force is an average; peak force during impact can be much larger.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (N)Local stepChange in result
m Mass0.001 to 100 kg6600,000600,000+10%+10 %
Δt Contact time0.5 to 100 ms489,6009,552+10%−9.09 %
v Final velocity21 to 100 m/s6723,2002,528+10%+10 %
u Initial velocity0 to 20 m/s320960640+10%0 %

Sweep of Contact time

Contact time (ms)Average force (N)
0.59,600
0.96964,950
1.882,553
3.6461,316
7.071678.8
13.71350
26.59180.5
51.5793.08
10048

Sweep one variable

Average force (N)Hover, touch, or use the arrow keys on the chart
0200040006000800010k 0.521050 Contact time (ms), log scale now 960

Variables and how each one contributes

F

Average force

Result · N

What the equation gives you. Everything else feeds it.

m

Mass

kg · typical 0.001 to 100

Mass of the object. Directly proportional.

u

Initial velocity

m/s · typical 0 to 20

Velocity before. Reduces the change.

v

Final velocity

m/s · typical 21 to 100

Velocity after. Increases the change.

Δt

Contact time

ms · typical 0.5 to 100

Duration of the force. Inversely proportional: doubling the time halves the force.

Worked example with the values above

  1. Change in momentum: m(v − u) = 0.16 × 30 = 4.8 kg·m/s.
  2. Time in seconds: 5 ms = 0.005 s.
  3. F = 4.8 / 0.005 = 960 N.

Assumptions and limits

  • Constant mass.
  • Force averaged over the contact time.

Common mistakes

  • Leaving time in milliseconds.
  • Wrong sign for a rebound.

Statistics and uncertainty

Contact time is hard to measure and short, so it dominates the uncertainty; a ±1 ms error on 5 ms is ±20% on the force.

Where it is used

  • Impact and recoil loads.
  • Protection and padding design.

Maths you need

  • Momentum: p = mv
  • Newton’s second law: F = Δp/Δt

Related formulas

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