Library / Mechanical / MEC-42
Mechanical
Lamé radial stress in a thick cylinder
Radial stress at radius r in a thick-walled cylinder under internal and external pressure.
- Ref
- MEC-42
- Rev
- v1
- Field
- Mechanical
- Result
- σr [MPa]
a and b are the internal (bore) and external radii, r is the radius where the stress is wanted (a ≤ r ≤ b), and pi and po are the internal and external pressures entered as positive values. Normal stress is positive in tension, so pressure gives a negative (compressive) radial stress at a loaded surface. The equations hold for a homogeneous, isotropic, linearly elastic cylinder with small deformation, away from the ends. The constants A and B come from the two boundary conditions σr(a) = −pi and σr(b) = −po. The defaults are the worked example from the reference sheet: a 50 mm bore, 75 mm outer radius and 10 MPa internal pressure.
Radial stress at radius r in a thick-walled cylinder under internal and external pressure. It equals minus the pressure at each surface and is always compressive for pressure loading.
Calculator
- Lamé constant A8 MPa
- Lamé constant B45,000 MPa·mm²
- Hoop stress at the same radius26 MPa
What drives the result
Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.
- The radial stress runs from −10 MPa at the bore to 0 at the outside surface, which are exactly the boundary conditions (−pi and −po). It is a good first check on any working.
- Under pressure the radial stress is compressive throughout and much smaller than the hoop stress (−10 against +26 MPa at the bore), so it is the hoop stress that governs failure.
Chart data as tables
Ranked variables
| Variable | Typical range | Lowest result | Highest result | Swing (MPa) | Local step | Change in result |
|---|---|---|---|---|---|---|
| pi Internal pressure | 1 to 100 MPa | −100 | −1 | 99 | +10% | +10 % |
| r Radial position in the wall | 50 to 75 mm | −10 | 0 | 10 | +10% | −31.2 % |
| a Internal radius | 10 to 100 mm | −10 | −0.2262 | 9.774 | +10% | — |
| po External pressure | 0 to 100 MPa | −10 | −10 | 5.684e-14 | +10% | 0 % |
| b External radius | 60 to 400 mm | −10 | −10 | 3.553e-15 | +10% | 0 % |
Sweep of Radial position in the wall
| Radial position in the wall (mm) | Radial stress (MPa) |
|---|---|
| 50 | −10 |
| 53.13 | −7.945 |
| 56.25 | −6.222 |
| 59.38 | −4.765 |
| 62.5 | −3.52 |
| 65.63 | −2.449 |
| 68.75 | −1.521 |
| 71.88 | −0.7108 |
| 75 | 0 |
Sweep one variable
Variables and how each one contributes
Radial stress
What the equation gives you. Everything else feeds it.
Internal pressure
The pressure acting on the inside (bore) surface, in MPa, entered as a positive value. At the default radius (the bore) the radial stress is exactly −pi, so a 10 % rise in pi makes σr 10 % more negative.
External pressure
The pressure acting on the outside surface, in MPa, entered as a positive value. Zero by default, which makes the radial stress 0 at the outside. External pressure makes it −po there and leaves the bore value at −pi: with po = 2 MPa the stress at mid-wall (62.5 mm) becomes −4.8 MPa instead of −3.5 MPa.
Internal radius
The internal radius (bore radius), in mm. Sets where the wall starts. The default r equals a, so raising a above r puts the point inside the bore, where there is no material and no result is shown: raise r with it.
External radius
The external radius, in mm. The wall thickness is b − a. The radial stress is still −pi at the bore and −po at the outside, but a thicker wall spreads the change between them more gradually. Thickening the wall helps the hoop stress far more than the radial stress.
Radial position in the wall
The radius at which the stress is wanted, in mm. It must lie in the wall, between a and b. Moves the point through the wall: at the defaults the radial stress rises from −10 MPa at the bore (50 mm) to −3.5 MPa at mid-wall (62.5 mm) and 0 at the outside (75 mm). The sweep chart shows the whole distribution.
Worked example with the values above
- Wall term: b² − a² = 75² − 50² = 3,125 mm².
- Lamé constants: A = (10 × 50² − 0 × 75²) / 3,125 = 8 MPa, and B = (10 − 0) × 50² × 75² / 3,125 = 45,000 MPa·mm².
- σr = A − B/r² = 8 − 45,000 / 50² = −10 MPa.
Assumptions and limits
- A homogeneous, isotropic, linearly elastic material with small deformation, so the stress stays below yield.
- Uniform internal and external pressure on a long cylinder, at a section away from the ends, nozzles and other discontinuities.
Common mistakes
- Entering a radius r that lies outside the wall. The result is only defined for a ≤ r ≤ b.
- Entering the pressures with a minus sign. Enter pi and po as positive values; the formula already makes the radial stress negative.
Statistics and uncertainty
σr is linear in the pressures, so a 1 % error in pi is a 1 % error here, and the values at the two surfaces depend on the pressures alone. Between the surfaces the 1/r² term makes the answer sensitive to the position: a 1 % error in r gives about a 2 % error in the B/r² part. In service the pressure is rarely known better than a few per cent and often has peaks above the nominal value, so treat the result as a nominal elastic stress, not a failure prediction.
Where it is used
- Checking the stress through the wall of a gun barrel, hydraulic cylinder or pressure vessel.
- Radial stress at the interface in shrink-fit and compound cylinder calculations.
Maths you need
- Radial and hoop stress: perpendicular normal stresses in a cylinder wall
- Algebra: substituting into A − B/r²