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Library / Fluid Mechanics / FLU-01

Fluid Mechanics

Force from a change in stream velocity

Force needed to change the velocity of a steady stream, from the momentum balance.

Ref
FLU-01
Rev
v1
Field
Fluid Mechanics
Result
F [N]

Fixed control volume with uniform velocity at each port. Include pressure forces, weight and wall forces on the fluid. The fluid exerts the opposite wall force on the pipe. For one inlet and outlet in the same direction ΣF = ṁ(V₂ − V₁).

Speeding up a stream of fluid takes a force equal to the mass flow rate times the speed change.

Calculator

Solve for
N
kg/s
0.15,000
m/s
0100
m/s
0100
  • Force in kN0.3 kN
  • Momentum flux at outlet500 N

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Net force on the fluid (N) current value 300 N
ṁMass flow rateKey driver
1.260,000
V₁Inlet velocity
−2,000500
V₂Outlet velocity
−2002,300
  • The fluid pushes back on the pipe with the opposite force: this is what a hose or nozzle feels.
  • Reversing the flow direction in a bend gives a force with both components.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (N)Local stepChange in result
ṁ Mass flow rate0.1 to 5,000 kg/s1.260,00060,000+10%+10 %
V₁ Inlet velocity0 to 100 m/s−2,0005002,500+10%−6.67 %
V₂ Outlet velocity0 to 100 m/s−2002,3002,500+10%+16.7 %

Sweep of Outlet velocity

Outlet velocity (m/s)Net force on the fluid (N)
0−200
12.5112.5
25425
37.5737.5
501,050
62.51,363
751,675
87.51,988
1002,300

Sweep one variable

Net force on the fluid (N)Hover, touch, or use the arrow keys on the chart
05001000150020002500 020406080100 Outlet velocity (m/s) now 300

Variables and how each one contributes

F

Net force on the fluid

Result · N

What the equation gives you. Everything else feeds it.

ṁ

Mass flow rate

kg/s · typical 0.1 to 5,000

Mass flowing through the control volume per second. Directly proportional.

V₁

Inlet velocity

m/s · typical 0 to 100

Velocity at the inlet. Lowers the force when larger.

V₂

Outlet velocity

m/s · typical 0 to 100

Velocity at the outlet. Raises the force.

Worked example with the values above

  1. Velocity change: V₂ − V₁ = 20 − 8 = 12 m/s.
  2. Multiply by ṁ = 25 kg/s.
  3. F = 300 N on the fluid.

Assumptions and limits

  • Steady flow with uniform velocity at each port.
  • Inlet and outlet along the same line.

Common mistakes

  • Forgetting pressure forces on the ports.
  • Losing the sign of the force direction.

Statistics and uncertainty

Flow rate and velocity are usually measured separately, so their relative errors add in quadrature.

Where it is used

  • Nozzle and jet reaction forces.
  • Pipe support and anchor loads at bends.

Maths you need

  • Mass flow rate: ṁ = ρAV
  • Newton’s second law: F = dp/dt

Related formulas

Practise this formula