Your Equation

Library / Electrical / ELE-08

Electrical

Resistivity

Resistance of a uniform conductor from its material, length and cross-sectional area.

Ref
ELE-08
Rev
v1
Field
Electrical
Result
R [Ω]

ρ in ohm-metres (Ω·m), L in metres, A in square metres. The calculator takes ρ in nΩ·m and A in mm².

A longer wire has more material to push charge through, and a thicker wire gives the charge more room. So resistance rises with length and falls with cross-sectional area. The resistivity ρ says how good the material is.

Calculator

Solve for
Ω
nΩ·m
101,500
m
11,000
mm²
0.550
  • Resistance per metre6.8 mΩ/m
  • Conductivity σ = 1/ρ58.82 MS/m

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Resistance (Ω) current value 0.68 Ω
ρResistivityKey driver
0.460
LLength
0.00686.8
ACross-sectional area
0.0343.4
  • R is proportional to L and ρ and inversely proportional to A. Doubling a cable’s cross-section halves its resistance and the voltage dropped along it.
  • The resistance per metre (a derived value) sets the voltage drop (V = IR) and the heating (I²R) along the cable.
  • For round conductors A = πd²/4, so a small increase in diameter has a large effect. 10% more diameter gives about 21% more area and about 17% less resistance.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (Ω)Local stepChange in result
ρ Resistivity10 to 1,500 nΩ·m0.46059.6+10%+10 %
L Length1 to 1,000 m0.00686.86.793+10%+10 %
A Cross-sectional area0.5 to 50 mm²0.0343.43.366+10%−9.09 %

Sweep of Length

Length (m)Resistance (Ω)
10.0068
2.3710.01613
5.6230.03824
13.340.09068
31.620.215
74.990.5099
177.81.209
421.72.868
1,0006.8

Sweep one variable

Resistance (Ω)Hover, touch, or use the arrow keys on the chart
0246 1520100500 Length (m), log scale now 0.68

Variables and how each one contributes

R

Resistance

Result · Ω

What the equation gives you. Everything else feeds it.

ρ

Resistivity

nΩ·m · typical 10 to 1,500

Property of the material at a given temperature: about 17 nΩ·m for copper, 27 for aluminium and 1100 for nichrome. Directly proportional: aluminium has about 1.6 times the resistivity of copper, so a cable needs about 1.6 times the area for the same resistance.

L

Length

m · typical 1 to 1,000

Length of the conductor along the current path. Directly proportional: doubling the length doubles the resistance.

A

Cross-sectional area

mm² · typical 0.5 to 50

Area of the conductor perpendicular to the current. Inversely proportional: doubling the area halves the resistance. For a round wire, area goes as diameter squared, so doubling the diameter divides R by four.

Worked example with the values above

  1. Convert to SI: ρ = 17 nΩ·m = 1.7×10−8 Ω·m, and A = 2.5 mm² = 2.5×10−6 m².
  2. R = ρL/A = (1.7×10−8 × 100) / 2.5×10−6 = 0.68 Ω.

Assumptions and limits

  • Uniform material and constant cross-section along the whole length.
  • Current spreads evenly over the cross-section. This holds for DC and low frequency; at high frequency the skin effect raises the resistance.
  • ρ is taken at the working temperature.

Common mistakes

  • Mixing area units: 1 mm² = 10−6 m², not 10−3 m².
  • Using diameter instead of area in the formula.
  • Forgetting the return path. A two-wire circuit has twice the one-way length.

Statistics and uncertainty

The formula is deterministic, but its inputs are uncertain. Because A depends on diameter squared, a 2% error in measured wire diameter gives about a 4% error in R. Resistivity also varies with temperature and purity, so tabulated values are typical, not exact.

Where it is used

  • Cable and busbar sizing against voltage drop.
  • Heating-element design.
  • Comparing copper and aluminium conductors.

Maths you need

  • Scientific notation and prefixes: nΩ·m to Ω·m and mm² to m²
  • Area of a circle: A = πd²/4 for a round wire

Related formulas

Practise this formula