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Library / Flight dynamics and control / FLT-04

Flight dynamics and control

Specific total energy rate

Rate of change of specific total energy, from the climb rate and the along-track acceleration.

Ref
FLT-04
Rev
v1
Field
Flight dynamics and control
Result
ėT [W/kg]

Differentiating eT = gh + Va²/2 gives ėT = gḣ + VaV̇a. The first term is the rate at which height is gained, the second the rate at which speed is gained, each per unit mass. In total-energy control the throttle sets the sum, and the elevator distributes it between climb and acceleration. The result is in W/kg.

Rate of change of specific total energy, from the climb rate and the along-track acceleration. Thrust sets the total, and the elevator moves energy between height and speed.

Calculator

Solve for
W/kg
m/s
−510
m/s
20300
m/s²
−11
  • Climb part, gḣ19.62 W/kg
  • Speed part, VaV̇a6 W/kg
  • Climb rate that the total could support at constant speed, ėT/g2.612 m/s

What drives the result

Each variable is moved across its typical range while the others stay at the values above. The longest bar is the key driver.

Specific total energy rate (W/kg) current value 25.62 W/kg
ḣClimb rateKey driver
−43.1104
V̇aAirspeed rate of change
−40.479.6
VaAirspeed
21.649.6
  • Of 25.62 W/kg, 19.62 goes into height and 6 into speed. Held at constant speed, the same 2 m/s climb would need only 19.62 W/kg; the other 6 W/kg is the cost of accelerating at the same time.
  • The energy rate equals the net power per unit mass, (T − D)Va/m for small angle of attack, where T is thrust and D drag. At 25.62 W/kg a 1000 kg aircraft needs about 25.62 kW of surplus power over drag.
Chart data as tables

Ranked variables

VariableTypical rangeLowest resultHighest resultSwing (W/kg)Local stepChange in result
ḣ Climb rate−5 to 10 m/s−43.05104.1147.2+0.3 m/s+11.5 %
V̇a Airspeed rate of change−1 to 1 m/s²−40.3879.62120+0.04 m/s²+9.37 %
Va Airspeed20 to 300 m/s21.6249.6228+10%+2.34 %

Sweep of Climb rate

Climb rate (m/s)Specific total energy rate (W/kg)
−5−43.05
−3.125−24.66
−1.25−6.263
0.62512.13
2.530.53
4.37548.92
6.2567.31
8.12585.71
10104.1

Sweep one variable

Specific total energy rate (W/kg)Hover, touch, or use the arrow keys on the chart
−50050100 −4048 Climb rate (m/s) now 25.62

Variables and how each one contributes

ėT

Specific total energy rate

Result · W/kg

What the equation gives you. Everything else feeds it.

ḣ

Climb rate

m/s · typical −5 to 10

The climb rate ḣ in m/s, positive up and negative in descent. Directly adds the climb term gḣ to the total: each extra metre per second of climb needs 9.81 W/kg. Raising it by 1 m/s (to 3 m/s) moves the result by +38.3 %, from 25.62 to 35.43 W/kg.

Va

Airspeed

m/s · typical 20 to 300

The airspeed in m/s. Multiplies the acceleration term: the same acceleration takes more energy at higher speed. Raising it by 10 % (to 66) moves the result by +2.34 %, from 25.62 to 26.22 W/kg.

V̇a

Airspeed rate of change

m/s² · typical −1 to 1

The airspeed rate of change in m/s², positive when accelerating. Directly adds the speed term VaV̇a to the total. Raising it by 0.1 m/s² (to 0.2 m/s²) moves the result by +23.4 %, from 25.62 to 31.62 W/kg.

Worked example with the values above

  1. Climb part: gḣ = 9.81 × 2 = 19.62 W/kg.
  2. Speed part: VaV̇a = 60 × 0.1 = 6 W/kg.
  3. ėT = 19.62 + 6 = 25.62 W/kg.

Assumptions and limits

  • Still air, constant gravity and a point-mass aircraft: the airspeed and the inertial speed are taken to be the same.
  • Small flight-path angles where the speed along the path is close to the speed through the air.

Common mistakes

  • Getting the sign of the climb rate wrong. Climb is positive here; descent is negative and removes potential energy.
  • Expecting throttle to command altitude and elevator to command speed. In total-energy control, throttle sets the total energy rate and pitch distributes it between height and speed.

Statistics and uncertainty

Both terms are measured quantities with different noise: climb rate comes from differentiating barometric or GNSS altitude, and acceleration from differentiating airspeed. Differentiation amplifies noise, so these rates are usually filtered or built from inertial sensors. A 0.05 m/s² error in the acceleration gives an energy-rate error of 3 W/kg at 60 m/s.

Where it is used

  • Total-energy control of throttle and pitch for fixed-wing aircraft.
  • Checking whether a climb or acceleration is paid for by thrust or by giving up speed.

Maths you need

  • Time derivative: the rate of change of a quantity
  • Power: energy per unit time

Related formulas

Practise this formula